Can anybody tell me all Formulae of Co-ordinate geometry?
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under root x 2 - X 1 the whole square
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ratio in x = mx2 + nx1 / m+n
ratio in y = mx2 +nx1 / m+ n
middle value of x line seg. = x1 + x2 / 2
middle value of y = y1 + y2 / 2
area of triangle = 1/2 underoot x1 (y2 -y3)+ x2 (y3-y1) + x3 (y1-y2)
to find the collinear points =
x1(y2,-y3) + x2 (y3-y1) + x3(y1-y2) always equal to 0
to find the length of sengment having two points ===
underoot (x2-x1)^2+ (y2-y1)^2
HOPE HELPS YOU
ratio in y = mx2 +nx1 / m+ n
middle value of x line seg. = x1 + x2 / 2
middle value of y = y1 + y2 / 2
area of triangle = 1/2 underoot x1 (y2 -y3)+ x2 (y3-y1) + x3 (y1-y2)
to find the collinear points =
x1(y2,-y3) + x2 (y3-y1) + x3(y1-y2) always equal to 0
to find the length of sengment having two points ===
underoot (x2-x1)^2+ (y2-y1)^2
HOPE HELPS YOU
Sayilesh:
it will help in my Exams of Tommorow Thanks Dude!
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