Question

can anybody tell me the answer of this question ​

Answer 1

p(x)x^3-2x^2+3x+7/x-2

zero of the polynomial. (x-2)

is 2

so ,now

p(2)=2^3-2(2)^2+3(2)+7

=8-2(4)+6+7

=8-8+6+7

8 and -8 get cancelled(as8-8=0)

=6+7

=13. is the final answer

hope it helps you

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Answer 2

Answer:

divisors is (x-2)

means x=2

p(x)=x^3-2x^2+3x+7

p(2)=2^3-2×2^2+3×2+7

=8-2×4+6+7

=8-8+6+7

=13