English, asked by chimatajyothika, 3 months ago

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Answers

Answered by aryansamdhyan008
2

Answer:

ANSWER

Given, 3x2+5x+2=0

On comparing this equation with ax2+bx+c=0, we get a=3,b=5 and c=2

Now, b2−4ac=(5)2−4×3×2

=25=24

=1

x=2a−b±b2−4ac

==2×3−5±1

=6−5±1

x=6−5+1

x=6−5−1

∴ 3−2 and −1 are the roots of the given quadratic equation.

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Answered by Dhannya24
4

Answer:

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