Question

Can anyone ans question 30?

Answer 1

Answer:

Explanation:

a))The short answer to this question is that the principal quantum number n must be larger than the angular momentum quantum number l. Thus, for n = 1, only l = 0 gives a valid wave function, for n = 2, you can only have l = 0, 1 (s and p), and so on. This condition follows from the requirement that the wave function needs to be square integrable.

b))The wave function psi by itself have no physical Significance. It shows the amplitude of electron wave ( wave function). However its square that is measures the probability of finding electron of giving energy from place to place in a giving region around the nucleus

c)).For the 5s orbital, n = 5 and l =0, therefore (n + l) = 5. An s subshell has only one orbital and as an orbital can hold a maximum of two electrons, therefore the maximum number of electrons that would be present in the 5s orbital would be 2

Answer 2

Explanation:

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