can Anyone ans This plzz fastly
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first we will draw a cyclic quadrilateral
by first observation angle A =60°
angle B =90°
angle C = 120°
and angle D = 90°
then angle A + angle C = 60° + 120°=180°
Angle B + angle D=90°+90°=180°
sum ofmeasure of all angles of cyclic quadrilateral must be 360°
let's do this more three times by taking various measures of angles of cyclic quadrilateral
you must see that the sum of measure of opposite angles of cyclic quadrilateral is 180 degree
by first observation angle A =60°
angle B =90°
angle C = 120°
and angle D = 90°
then angle A + angle C = 60° + 120°=180°
Angle B + angle D=90°+90°=180°
sum ofmeasure of all angles of cyclic quadrilateral must be 360°
let's do this more three times by taking various measures of angles of cyclic quadrilateral
you must see that the sum of measure of opposite angles of cyclic quadrilateral is 180 degree
greeshma93:
tqs a lot
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