Can anyone answer 1,2 and 3 questions or just simply answer any 1. Fast
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Q no(.3)ar(∆PQRS)=at(∆ABRS) as they are on the same base RS.
ar(∆AXS)=1/2ar(ABRS) as they are on the same base AS & between the same parallels AS & BR.
at(ABRS)=at(PQRS). (proved above). Therefore, ar(AXS)=ar(PQRS)
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