Question

can anyone answer it immediately​

Answer 1

Step-by-step explanation:

2^a²+ab / 2^ab+b² x 2^b²+bc / 2^bc+c² x 2^c²+ac / 2^ac+a²

2^(a²+ab+b²+bc+c²+ac) / 2^(ab+b²+bc+c²+ac+a²)

2^[a²+ab+b²+bc+c²+ac - (ab+b²+bc+c²+ac+a²)]

2^[a²+ab+b²+bc+c²+ac - ab-b²-bc-c²-ac-a²]

2^0

1 = R.H.S proved.

Answer 2

Answer:

 

2^a²+ab / 2^ab+b² x 2^b²+bc / 2^bc+c² x 2^c²+ac / 2^ac+a²

2^(a²+ab+b²+bc+c²+ac) / 2^(ab+b²+bc+c²+ac+a²)

2^[a²+ab+b²+bc+c²+ac - (ab+b²+bc+c²+ac+a²)]

2^[a²+ab+b²+bc+c²+ac - ab-b²-bc-c²-ac-a²]

2^0

=1