can anyone answer it pls
Attachments:
Answers
Answered by
1
Hello there,
I hope my answer is correct.
a) 135/230=27/46
b) 130/230=13/23
c) 10/230=1/23
Make the problem like this,
More than 1750 : 10
More than 1775 : 45
.......
Hope you got the correct answer.
Please mark it as the brainliest of this is correct.
rookie54:
thanks for help
Answered by
1
first of all we have to find out the n(s) of the given observation
so, n(s) = 10+45+75+60+40
= 230
now,
let A be the event of getting rs 1800 or more but less than rs.1825
therefore, n(A) = 75
therefore p(A) = n(A)/n(s)
= 75/230
= 17/46
now,
let b be the event of getting below rs 1825
so, n(b) = 10+45+75
= 130
therefore, p(b)= n(b)/n(s)
= 130/230
=13/23
now,
let c be the event of getting at least rs1775
so, n(c) = 10
therefore, p(c) = n(c)/n(s)
=10/230
=1/230
so, n(s) = 10+45+75+60+40
= 230
now,
let A be the event of getting rs 1800 or more but less than rs.1825
therefore, n(A) = 75
therefore p(A) = n(A)/n(s)
= 75/230
= 17/46
now,
let b be the event of getting below rs 1825
so, n(b) = 10+45+75
= 130
therefore, p(b)= n(b)/n(s)
= 130/230
=13/23
now,
let c be the event of getting at least rs1775
so, n(c) = 10
therefore, p(c) = n(c)/n(s)
=10/230
=1/230
Similar questions