Question

can anyone answer
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answer only if u know the answer
pls
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Answer 1

Answer:

The three terms are 2, 9, 16

Step-by-step explanation:

Given, the sum of three consecutive terms in Arithmetic Progression is 27 and their product is 288.

The three consecutive numbers in Arithmetic Progression can be represented as a-d, a, a+d.

Sum; (a-d)+a+(a+d) = 27

3a-d+d = 27

3a = 27

a = 9

Product; (a-d)*a*(a+d) = 288

a*(a²-d²) = 288 [ Because (a-b)*(a+b) = a²-b² ]

a³-ad² = 288

Substituting, a=9,

9³-9*d² = 288

729-9d² = 288

729-288 = 9d²

441 = 9d²

d² = 441/9

d² = 49

d = 7

Therefore, the terms are 9-7, 9, 9+7; which are 2, 9, 16

Answer 2

Answer:

2. trade

3.3th

Step-by-step explanation:

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