Question

can anyone answer the 10 question ​

Answer 1

Let E1 be energy for bulb

E2 be tubelight

E3 be refrigerator

Now

E1 = 3 * 40 * 6

= 720 kWh

E2 = 4*50*6

=1200 kWh

E3 = 320 * 24

= 7680 kWh

Now total energy for 1 day =

E1 + E2 + E3

= 9600 kWh

It is given that this was used for 30 days

So 9600 * 30

Total energy for a month = 288,000 KWh

Money per kWh = rs 2.50

For total energy = 2.50 * 288000

= Rs 720000