Question

Can anyone answer the 1st, 6th,and 7th pls i need the answer ASAP

Answer 1

I hope it's help you☺️ okay

1).2√5×5×5+√3³+2√2×2×3

10√5+3√3+2√3

10√5+5√3

5(2√5+√3)

if you remember √3= 1.732 and √5=2.236

then put value and get perfect answer

2).(x-1) and (x+1)is factor

put,
x= 1

0= a+b+c+d

put,
x= -1

0= -a+b-c+d

a+b+c+d=-a+b-c+d

a+a+b-b+c+c+d-d=0

2a+2c=0

a+c=0

3). a²(ac.ab)+b²(bc.ab)+c²(bc.ac)/bc.ac.ab

a⁴cb+b⁴ac+c⁴ab/b²a²c²

abc(a³+b³+c³)/b²a²c²

a³+b³+c³/abc

a³+b³+c³=(a+b+c)³-3(b+c)(c+a)(a+b)

(a+b+c)³-3(b+c)(c+a)(a+b)/abc

(0)³-3(b+c)(c+a)(a+b)/abc

given a+b+c=0
b+c=-a ; a+b=-c ; a+c=-b

-3(-a)(-b)(-c)/abc

3

LHS=RHS