can anyone answer these questions its really urgent i really need it now pls someone help answer any questions pls guys it would be really nice of u all
Answers
Answer:
Basic Concept :
✴ Eq. resistance of series :
⇒ Rs = R1 + R2 + ... + Rn
✴ Eq. resistance of parallel :
⇒ 1/Rp = 1/R1 + 1/R2 + ... + 1/Rn
⎆ As per ohm's law, Current flow through a conductor is directly proportional to the applied potential difference.
Mathematically, V = IR
✴ SoluTion - 6)
➾ 1,2 and 3 are in series :
▪ R123 = R1 + R2 + R3
▪ R123 = 60 + 20 + 35
▪ R123 = 115Ω
➾ 123 and 4 are in parallel :
▪ 1/R = 1/R123 + 1/R4
▪ 1/R = 1/115 + 1/14
▪ R = (115×14)/(115+14)
▪ R = 1610/129
▪ R = 12.48Ω
➾ Curren flow :
▪ V = IR
▪ I = 5/12.48
▪ I = 0.4A
✴ SoluTion - 7)
➨ 1 and 2 are in series :
▪ R12 = R1 + R2
▪ R12 = 4 + 4
▪ R12 = 8Ω
➨ 3 and 4 are in series :
▪ R34 = R3 + R4
▪ R34 = 4 + 4
▪ R34 = 8Ω
➨ R12 and R34 are in parallel :
▪ 1/R = 1/R12 + 1/R34
▪ 1/R = 1/8 + 1/8
▪ R = 8/2
▪ R = 4Ω
➨ Current flow :
▪ V = IR
▪ I = 1.5/4
▪ I = 0.375A
✴ SoluTion - 5)
➜ R1 and R2 are in parallel :
▪ 1/R12 = 1/R1 + 1/R2
▪ 1/R12 = 1/6 + 1/6
▪ R12 = 3Ω
➜ R3 and R4 are in parallel :
▪ 1/R34 = 1/R3 + 1/R4
▪ 1/R34 = 1/6 + 1/6
▪ R34 = 3Ω
➜ R12 and R34 are in series :
▪ R = R12 + R34
▪ R = 3 + 3
▪ R = 6Ω
➜ Current flow :
▪ V = IR
▪ I = 3/6
▪ I = 0.5A