Can anyone answer these three questions, please?
I will surely mark the answer as brainliest! Please!
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mona80:
16 questions ans 380 17 questions ans 12 and 18 questions ans is 3.42
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Answered by
61
Let the length of another train = x.
Given that the speed of the one train = 90kmph.
Given that the speed of another train = 54kmph.
Relative speed of the train = (90 + 54) km/hr
= 144 km/hr
= 144 * 5/18 m/sec
= 720/18 m/sec
= 40 m/sec.
Given that the length of the train is 180m and two trains cross each other = 16sec.
180 + x/40 = 16
180 + x = 16 * 40
180 + x = 640
x = 640 - 180
x = 460.
Therefore the length of the other train = 460m.
(18) 97.5 * 10^17 - 6.32 * 10^18
= > 9.75 * 10^18 - 6.32 * 10^18
= > 3.43 * 10^18
= > 7^3 * 10^16.
Hope this helps!
Given that the speed of the one train = 90kmph.
Given that the speed of another train = 54kmph.
Relative speed of the train = (90 + 54) km/hr
= 144 km/hr
= 144 * 5/18 m/sec
= 720/18 m/sec
= 40 m/sec.
Given that the length of the train is 180m and two trains cross each other = 16sec.
180 + x/40 = 16
180 + x = 16 * 40
180 + x = 640
x = 640 - 180
x = 460.
Therefore the length of the other train = 460m.
(18) 97.5 * 10^17 - 6.32 * 10^18
= > 9.75 * 10^18 - 6.32 * 10^18
= > 3.43 * 10^18
= > 7^3 * 10^16.
Hope this helps!
Answered by
0
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