Can anyone answer this..?
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here is ur answer......
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Heya User,
--> Let's see !!!
--->ABCD is a ||gm..
Hence, --> AB = CD ..
---> Given, AE = CF
Also,----->∠BAE = ∠DCF
Hence, ΔBAE ≅ ΔDCF ..
Similarly, you can prove :->
---> ΔDAE ≅ ΔBCF <-- From where you'd get :->
---> BE = DF and DE = BF and also, -->
----> ∠BEF = ∠DFE
--> hence, you can prove :-> BFDE is a ||gm
--> Let's see !!!
--->ABCD is a ||gm..
Hence, --> AB = CD ..
---> Given, AE = CF
Also,----->∠BAE = ∠DCF
Hence, ΔBAE ≅ ΔDCF ..
Similarly, you can prove :->
---> ΔDAE ≅ ΔBCF <-- From where you'd get :->
---> BE = DF and DE = BF and also, -->
----> ∠BEF = ∠DFE
--> hence, you can prove :-> BFDE is a ||gm
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