Question

can anyone answer this only one pls​

Answer 1

Step-by-step explanation:

let the first term be a.

the common difference be d.

then the sum of first three term= a+a+a+d+2d=3a+3d

Given 3(a+d)=33

a+d=11

d=11-a

Therefore the second term of AP=11

the product of 1 and 3 term=(a)(a+2d)=a(a+2(11-a)

=a(a+22-2a)

=a(22-a)

=22a-a square

A.T.Q , given = 22a-a square -29 = a+d

22a- a square -29 =11

22 a- a square - 40=0

a square -22a +40 =0

a square - 20a -2a + 40=0

a(a-20)-2( a-20)=0

a=2 or a=20

finding common difference for

a=2

11-2=9

finding common difference for

a=20

11-20=-9

NOW ALL POSSIBLE A.P are

1. 2, 11, 20, 29, 38, 47, ..........
2. 20, 11, 2, -7, -16, -25, -34, -43, .......