Question

can anyone answer this pls​

Answer 1

Step-by-step explanation:

THAT IS AN ISCOSCELES TRIANGLE SO THEIR ANGLES WILL BE SAME THE SUM OF ALL THE INTERIOR ANGLES OF THE TRIANGLE IS 180

40+X+X=180

40+2X=180

2X=180-40

2X= 140

X=140/2

X=70= ANGLE B

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THANKYOU

Answer 2

$\huge{\bf{\green{\mathfrak{\dag{\underline{\underline{Question:-}}}}}}}$

$\bullet{\leadsto}$ In ∆ABC, AB = AC and angle A = 40°, Find angle B.

$\huge {\bf{\orange{\mathfrak{\dag{\underline{\underline{Answer:-}}}}}}}$

$\bullet{\leadsto} \: \sf \triangle ABC \: is \: given.$

$\bullet{\leadsto} \: \sf AB \: = \: AC.$

$\bullet{\leadsto} \: \pink{\sf \implies \triangle ABC \: is \: a \: isosceles \: triangle.}$

$\bullet{\leadsto} \: \sf Then, \: angle \: B \: = \: angle \: C.$

$\bullet{\leadsto} \: \sf angle \: A \: = \: 40^{\circ}$

$\bullet{\leadsto} \: \textsf{We know that,}$

$\bullet{\leadsto} \: \boxed{\sf angle \: A \: + \: angle \: B \: + \: angle \: C \: = \: 180^{\circ}. \: (Angle \: sum \: property)}$

$\bullet{\leadsto} \: \textsf{Substituting the values,}$

$\bullet{\leadsto} \: \sf angle \: A \: + \: angle \: B \: + \: angle \: C \: = \: 180^{\circ}.$

$\bullet{\leadsto} \: \sf 40^{\circ} \: + \: angle \: B \: + \: angle \: C \: = \: 180^{\circ}.$

$\bullet{\leadsto} \: \sf 40^{\circ} \: + \: 2 (angle \: B) \: = \: 180^{\circ}. \: ({angle \: B \: = \: angle \: C})$

$\bullet{\leadsto} \: \sf \: 2 (angle \: B) \: = \: 180^{\circ} \: - \: 40^{\circ}$

$\bullet{\leadsto} \: \sf \: 2 (angle \: B) \: = \: 140^{\circ}$

$\bullet{\leadsto} \: \sf angle \: B \: = \: \dfrac{140^{\circ}}{2}$

$\bullet{\leadsto} \: \boxed{\blue{\sf angle \: B \: = \: 70^{\circ}.}}$

$\huge{\bf{\red{\mathfrak{\dag{\underline{\underline{Conclusion:-}}}}}}}$

$\bullet{\leadsto} \: \boxed{\therefore{\sf angle \: B \: = \: x^{\circ} \: = \: 70^{\circ}.}}$