Question

can anyone answer this question?
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Answer 1

Answer:

\bf{\frac{x^2}{36}-\frac{y^2}{64}=1}36x2−64y2=1

Step-by-step explanation:

\text{Formula used:}Formula used:

cosec^2A-cot^2A=1cosec2A−cot2A=1

\text{Given:}Given:

x=6\:cosec\theta\:\text{and}\:y=8\:cot\thetax=6cosecθandy=8cotθ

\implies\:\frac{x}{6}=cosec\theta\:\text{and}\:\frac{y}{8}=cot\theta⟹6x=cosecθand8y=cotθ

\text{we know that}\:cosec^2\theta-cot^2\theta=1we know thatcosec2θ−cot2θ=1

\implies\:(\frac{x}{6})^2-(\frac{y}{8})^2=1⟹(6x)2−(8y)2=1

\implies\:\frac{x^2}{36}-\frac{y^2}{64}=1⟹36x2−64y2=1