Can anyone answer this question for me...
If alpha and beta are the roots of x²+x-2.....
Find the value of. 1/alpha - 1/beta...
Pls and...would do a lot of help ..
Answers
Answered by
3
let roots of equation a
and b
now
1/a -1/b = b-a/ab ....(1)
from equation
ab = -2 ....(2)
a+b = -1
now
(a+b)^2 = (a - b)^2 +
4ab
so
1 = (a-b)^2 - 8
a - b = √9
a-b = 3
then
b-a = -3 ...(3)
put value of ab and b-a
from equation. (2) & (3) in equation (1)
so
1/a - 1/b = -3/-2
= 3/2
##hope it can help you ##
and b
now
1/a -1/b = b-a/ab ....(1)
from equation
ab = -2 ....(2)
a+b = -1
now
(a+b)^2 = (a - b)^2 +
4ab
so
1 = (a-b)^2 - 8
a - b = √9
a-b = 3
then
b-a = -3 ...(3)
put value of ab and b-a
from equation. (2) & (3) in equation (1)
so
1/a - 1/b = -3/-2
= 3/2
##hope it can help you ##
Answered by
0
This is the answer......
A(alpha) - B(beta) = ((A+B)-4AB)^
A(alpha) - B(beta) = ((A+B)-4AB)^
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