Question

Can anyone answer this question in attachment..

Answer 1

Hii..
Here is ur answer.. Hope this helps..

Answer 2

Answer:

AB || CD

Step-by-step explanation:

From figure:

Since, BM ⊥ PQ, CN ⊥ RS

∴ BM || CN

∠MBC = ∠NCB {Alternate interior angles}   ---- (i)

∠ABM = ∠MBC {Angle of incidence = Angle of reflection}  ---- (ii)

∠NCB = ∠NCD {Angle of incidence = Angle of reflection}  ----- (iii)

From (i), (ii) and (iii), we get

∠ABM = ∠NCD  ----- (iv)

On adding (i) & (iv), we get

∠MBC + ∠ABM = ∠NCB + ∠NCD

⇒ ∠ABC = ∠BCD

But these are alternates angles and they are equal.

Hence, AB || CD.

Hope it helps!