can anyone can solve this problem please
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triangle QRS IS rt.angled
by pythagoars theo.
(QS)*2=(RS)*2+(RQ)*2
=(11)*2+(60)*2
=121+3600
= 3721
QS=
QS=61m
NOW,ar of triangleQRS
=1/2×B×H
=1/2×60×11
=330m*2
AR OF TRIANGLE QTS
= 1/2× 61×26
=793m*2
ar of triangle PQT
=1/2×36×10
=180m*2
NOW AREA OF PQRTS
=330+793+180
=1303
HOPE IT WILL HEPL UU.....
triangle QRS IS rt.angled
by pythagoars theo.
(QS)*2=(RS)*2+(RQ)*2
=(11)*2+(60)*2
=121+3600
= 3721
QS=
QS=61m
NOW,ar of triangleQRS
=1/2×B×H
=1/2×60×11
=330m*2
AR OF TRIANGLE QTS
= 1/2× 61×26
=793m*2
ar of triangle PQT
=1/2×36×10
=180m*2
NOW AREA OF PQRTS
=330+793+180
=1303
HOPE IT WILL HEPL UU.....
yuvraj765:
please mark it as brainliest
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