Question

can anyone do explain it step by step?​

Answer 1

Answer:

$\frac{3t - 2}{4} - \frac{2t + 3}{3} = \frac{2}{3} - t \\ \frac{3(3t - 2) - 4(2t + 3)}{12} = \frac{2 - 3t}{3} \\ \frac{9t - 6 - 8t - 12}{12} = \frac{2 - 3t}{3} \\ \frac{9t - 8t - 6 - 12}{12} = \frac{2 - 3t}{3} \\ \frac{t - 18}{12} = \frac{2 - 3t}{3} \\ 3(t - 18) = 12(2 - 3t) \\ 3t - 54 = 24 - 36t \\ 3t + 36t = 24 + 54 \\ 39t = 78 \\ t = \frac{78}{39} \\ t = 2$

I hope it will help you

Answer 2

Step-by-step explanation:

$\frac{3t - 2}{4} - \frac{2t + 3}{3} = \frac{2}{3} - t$

cross multiplication of left hand side no.

$\frac{(3t - 2)3 - (2t + 3)4}{12} = \frac{2}{3} - t$

$\frac{9t - 6 - 8t - 12}{12} = \frac{2}{3} - \frac{t}{1}$

cross multiplication of right hand side no.

$\frac{9t - 6 - 8t - 12}{12} = \frac{2 - 3t}{3}$

cross multiplication

$( 9t - 6 - 8t - 12)3 = (2 - 3t)12$

=

$27t - 18 - 24t - 36 = 24 - 36t$

=

$27t + 36t - 24t = 24 + 36 + 18$

=

$49t = 78$

=

$t = \frac{78}{49}$