Question

can anyone do it????​

Answer 1

Explanation:

hey buddy the answer is 5g

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Answer 2

Solution :-

• Let the mass of glucose required = x grams.

Given :-

• mass/mass solution = 10%
• mass of water = 45 gm

i. e.

(mass of glucose)(Total mass of solution)× 100 = 10

$\frac{x}{(x+45)}$ ×100 = 10

$\implies$ 100x= 10(x+45)

$\implies$ 100x = 10x + 450

$\implies$ 100x- 10x =450

$\implies$ 90x = 450

$\implies$ x = $\bf\dfrac{450}{90}$ = 5grams.