Question

Can anyone do it ?
Plz help me​

Answer 1

Given -

$\angle \: p = \frac{1}{2} \angle \: q$

To find -

The values of p and q

Solution -

We know that

p+q=180°[Linear pair]........ 1)

Now putting the value of p we will get

$\frac{1}{2}\angle \: q + \angle \: q = 180$

$\frac{1 + 2}{2}\angle q = 180$

$\frac{3}{2} \angle \: q = 180$

$3 \: \angle \: q = 180 \times 2$

$\angle \: q = \frac{180 \times 2}{3}$

$\angle \: q = 120$

Now putting the value of q in equation 1) we will get -

$\angle \: p + \angle \: q = 180$

$\angle \: p + 120 = 180$

$\angle \: p = 180 - 120$

$\angle \: p = 60$

$\therefore \: The \: value \: of \: \angle \: p \: is \: {60}^{0} \: and \: \\ value \: of \: \angle \: q \: is \: {120}^{0}$