Question

can anyone do the 2nd part of 13 (q) please i need it with proper steps​

Answer 1

Answer:

13) 3y - 2x = 1

(ii)

put x = 2√2 & y = 3√2

we get,

LHS = ( 3 × 3√2 ) - (2 × 2√2) = (9√2-4√2)

= 5√2

RHS = 1

Therefore LHS ≠ RHS

hence (2√2,3√2) is not a solution of 3y - 2x = 1

Answer 2

Answer:

the First is Solution for equation.. but second is not..