Math, asked by uzairmajal3, 8 hours ago

Can anyone do this for 35 points​

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Answers

Answered by prithika27555
1

Answer:

secx=(

2

−1)tanx+1

1+tan

2

x=(3−2

2

)tan

2

x+1+2tanx(

2

−1)

tan

2

x(2−2

2

)+2tanx(

2

−1)=0

tan

2

x(1−

2

)+tanx(

2

−1)=0

tanx(tanx(1−

2

)+(

2

−1)=0

tanx=1

x=nπ±

4

π

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