Can anyone do this for 35 points
Attachments:
![](https://hi-static.z-dn.net/files/dd7/159d3ef80efc77a6ef8f8fbe4a94b15f.jpg)
Answers
Answered by
1
Answer:
secx=(
2
−1)tanx+1
1+tan
2
x=(3−2
2
)tan
2
x+1+2tanx(
2
−1)
tan
2
x(2−2
2
)+2tanx(
2
−1)=0
tan
2
x(1−
2
)+tanx(
2
−1)=0
tanx(tanx(1−
2
)+(
2
−1)=0
tanx=1
x=nπ±
4
π
Similar questions