Question

can anyone do this real quick i have to check my answer


evaluate:
tan (-26π/3)

Answer 1

$Given : tan( \frac{-26 \pi }{3} )$

We know that tan(-x) = -tanx.

$= \ \textgreater \ -tan( \frac{26 \pi}{3} )$

$= \ \textgreater \ -tan( \frac{24 + 2}{3} ) \pi$

$= \ \textgreater \ -(8 + \frac{2}{3} ) \pi$

$= \ \textgreater \ -( \pi * 8 + \frac{2}{3} \pi )$

$= \ \textgreater \ -tan( \frac{2}{3} \pi )$

$= \ \textgreater \ -tan( \frac{2 \pi }{3} )$

$= \ \textgreater \ -(- \sqrt{3})$

$= \ \textgreater \ \sqrt{3}$



Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks