can anyone do this sum
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→ 12x + 15
= 3 ( 4x + 5 )
→ 16a² - 24ab
= 8a ( 2a- 3b)
and so on...
At first Select common .
apply some identites to solve .
Its too easy ,
As
x² - 5x + 6
= x² -3x -2x + 6
= x ( x - 3) -2 ( x - 3)
= ( x - 2 ) ( x - 3 )
OK
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