Math, asked by hihihi56, 1 year ago

can anyone explain factorization​

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Answered by ButterFliee
0

 \frac{ {p}^{2}  - 2pq +  {q}^{2} }{3}  = 0 \\  {p}^{2}  - 2pq +  {q}^{2}  = 0 \\  {p}^{2}  - (pq + pq) +  {q}^{2}  = 0 \\  {p}^{2}  - pq - pq +  {q}^{2}  = 0 \\ p(p - q) - q(p - q) = 0 \\ (p - q)(p - q)

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