Question

Can anyone explain in details the trigonometric integration function of cos^ 3 x sin x dx?
Here, which formula we need to use cos^2x=1-sin^2x or sin^2x=1-cos^2x

Answer 1

Answer:

I hope you got the answer to your query...

If yes, then don't forget to mark it as the BRAINLIEST ANSWER.

Answer 2

Answer:

I can explain in details...........

Step-by-step explanation:

given that ..

integration cos^3(x ) sinx

we will solve on-------

integration by sabstitution mathod.....

sol....

integration cos^3(x) sinx dx

now we can use....(cos^2x=1-sin^2x) because questions is saying we need to use this..

so,

we can write,

cos x cos^2 sinx

cos{1-sin^2(x)} sinx

cos x {sinx -sin^3(x)}

cos x sinx -cosx sin^3(x)

now we will integration in different parts

integral cos x sinxdx - integral cosx sin^3xdx

sapo's that,

sinx=t. (sabstitution mathod)

derivations on both sides.....

cosx=dt/dx

dx=dt/cosx

put on value,

integral cosx t dt/cosx - integral cosx sin^3x dt /cosx .

integral tdt - integral t^3

.

1/2t^2- 1/4t^4.... (x^n+1/n+1)

1/2sin^2(x) - 1/4 sin^4(x). write answer

hope this helps..

if I explained in details and my answer is write then please mark as brainlist me for motivation......