Question

can anyone explain me this question​

Answer 1

Answer:

It's (a-b+c)² = a²+b²+c²+(-2ab) +(-2bc) +2ac

sin

Answer 2

Step-by-step explanation:

(a-b+c)²=a²+b²+c²-2ab-2bc+2ac

according to the question,

a=1

b=sin theta

c=cos theta