Can anyone explain the answer? Help will be appreciated...Please REPLY in detail.
Simplify the following:
![\sqrt[4]{12} X \sqrt[7]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B12%7D+X+%5Csqrt%5B7%5D%7B6%7D "\sqrt[4]{12} X \sqrt[7]{6}")
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Answer:
Step-by-step explanation:
12 can be written as 2²×3
so 12 ^1/4 can be wriiten as 2^1/2 × 3^1/4
6 can be written as 2 × 3
so 6^1/7 can be written as 2^1/7 × 3^1/7
so 12 ^1/4 × 6^1/7 = 2^(1/7+1/2) × 3^(1/7+1/4)
= 2^9/14 × 3^11/28
vamshimadineni123:
3^11/28 can be written as 3^9/14 / 3^1/4
so answer is 6^9/14 /3^1/4
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