Question

can anyone explain this in steps please

Answer 1

here

$\frac{ \alpha + \beta }{ \alpha \times \beta } = \frac{ \frac{18}{p} }{ \frac{9}{p} } \:$

in the next step

$\frac{ \alpha + \beta }{ \alpha \times \beta } = \frac{18}{9} \\ here \: both \: p \: got \: cancled$

then the fraction becomes

$\frac{1}{ \beta } + \frac{1}{ \alpha } = \frac{18}{9}$

Answer 2

Answer:

$\frac{ \alpha \: + \beta}{ \alpha \beta} = \frac{ \frac{18}{p} }{ \frac{9}{p} } \\ \\ \\ \frac{ \alpha}{ \alpha \beta} + \frac { \beta}{ \alpha \beta} = \frac{18}{p} \div \frac{9}{p} \\ \\ \frac{1}{ \beta} + \frac{1}{ \alpha} = \frac{18}{p} \times \frac{p}{9} \\ \\ \\ { \red{ \large{\frac{1}{ \beta} + \frac{1}{ \alpha} = \frac{18}{9} }}}$