Can anyone explain this step.I couldnt understand it,
Point P=(-5,2) A(a,0) B(0,b)
Given P divides AB in the ratio 2:3
P=(3a/5,2b/5) ??????????????
Please anwser it quick.
psanjay900:
THE last step i couldn't understand .
this locus question
no straight lines
please be quick @honeyvsb
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Given P = (-5, 2)
A = (a, 0)
B = (0, b)
Let m:n = 2:3 (ratio in which P divides AB)
W.K.T.,
P = ((mx2+nx1)/(m+n) , (my2+ny1)/(m+n))
P = ((2(0)+3(a))/(2+3) , (2(b)+3(0))/(2+3))
P = (3a/5 , 2b/5)
By comparing P = (-5, 2) and P = (3a/5, 2b/5)
We get a = -25/3
b = 5
Therefore, A = (-25/3 , 0)
B = (0, 5)
A = (a, 0)
B = (0, b)
Let m:n = 2:3 (ratio in which P divides AB)
W.K.T.,
P = ((mx2+nx1)/(m+n) , (my2+ny1)/(m+n))
P = ((2(0)+3(a))/(2+3) , (2(b)+3(0))/(2+3))
P = (3a/5 , 2b/5)
By comparing P = (-5, 2) and P = (3a/5, 2b/5)
We get a = -25/3
b = 5
Therefore, A = (-25/3 , 0)
B = (0, 5)
Hey W.K.T.
W.K.T means we know that (it is a formula of internal point)
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