*can anyone explain this sum*
(AB²-BC
(6 km) + (8 km)
V
36 + 64 km = 10 km
Answers
Answered by
1
Answer:
I think you say
The Pythagorean theorem,
Hypotenuse^2 = Perpendicular^2 + Base^2
please make me as a brainliest
Answered by
0
Answer:
It must be a problem of Pythagoras Theorem.
Explanation:
It must have given
In ∆ABC, Angle B =90°
AB= 6 km and BC= 8 km
So by applying the Pythagoras Theorem
(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2
=> AC^2 = AB^2 + BC^2
=> AC= √(AB^2 + BC^2)
=> AC= √(6^2 + 8^2)
=> AC= √(36 + 64)
=> AC= √100
=> AC= 10 km ........................ (Ans)
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