Can anyone explain why height is subtracted only once from an open cuboid?
Answers
Answer:
What is the surface area of an open cuboid box having each edge as 5cm?
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There are several methods of doing this question .
But the easiest one is given below:-
First find Total Surface Area of whole cuboid which is ,
Given,
Length (l) = 5cm
Breadth (b) = 5cm
Height (h) = 5cm
TSA of cuboid = 2(l*b+b*h+h*l)
= 2(5*5+5*5+5*5)
= 2(25+25+25)
= 2(75)
= 150 sq cm
Now , we know that box is open from top so we have to subtract Area of rectangle from TSA .
Area of rectangle = l*b
= 5*5
= 25 sq cm
Now,
The surface area of open cuboidal box
= TSA of cuboidal box - Area of rectangle
= 150 - 25
= 125 sq cm
Hence,
Answer - 125 sq cm
Explanation:
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Answer:
Length of the cuboid = 20 cm
Breadth of the cuboid = 15 cm
Height of the cuboid = 10 cm
Therefore, volume of the cuboid = length × breadth × height
= (20 × 15 × 10) cm³
= 3000 cm³