can anyone factorise me -2k(square) +4k-2=0
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Answered by
57
-2k^2 + 4k - 2 = 0
-2k^2 +2k + 2k - 2 = 0
-2k(k - 1) +1(k - 1) = 0
(k - 1)(-2k + 1) = 0
=> (k - 1) = 0 or (-2k + 1) = 0
=> k = 1 or k = 1/2
Answered by
2
Answer:
BY SPLITTING MIDDLE TERM
Step-by-step explanation:
-2k² + 4k - 2 = 0
-2k² + 2k + 2k -2 = 0
-2k ( k - 1 ) + 2 (k - 1) = 0
(-2k + 2) (k - 1) = 0
-2k + 2 = 0
- k = 1
- k - 1 = 0
- k = 1
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