Question

can anyone find the equivalent resistance​

Answer 1

Hey Friend!

Here is your answer:

Formula Section:

When resistance are connected in a series, equivalent resistance = R₁ + R₂ + R₃ + ...$R_{n}$

When resistances are connected in parallel, equivalent resistance = ( 1/R₁ + 1/R₂ + 1/R₃ + ...1/$R_{n}$)⁻¹

Equivalent Resistance between A and B has three connections in parallel where there are series resistances too

Equivalent resistance between the first series is ( 10 + 10 ) Ω = 20 Ω

Equivalent resistance between the second series is ( 10 + 10 ) Ω = 20  Ω

Now, we are only left with 3 parallel connections,

Equivalent resistance between A and B is ( $\frac{1}{20} + \frac{1}{10} + \frac{1}{20}$ )⁻¹  Ω

                                                        = ( $\frac{1 + 2 + 1}{20}$ ) ⁻¹  Ω

                                                        = ( $\frac{4}{20}$ )⁻¹  Ω

                                                        = $(\frac{1}{5} )$⁻¹  Ω

                                                        = 5  Ω

Hence, your answer is 5  Ω

I hope you understand. And if you appreciate my answer please respond with a thanks!