Question

can anyone give me answer of these .. no spam warning or i report your answer​

Answer 1

Given

• $\sf \: a = \frac{ - 4}{9} \: \: \: b = \frac{7}{3} \: \: \:   c = \frac{11}{6}$

Show That

• $(a - b) - c ≠a - (b - c)$

Let

$\sf \: LHS = (a - b) - c$

$\sf \: LHS = ( \frac{ - 4}{9} -( \frac{7}{3} )) - \frac{11 }{6}$

$\sf \: LHS = ( \frac{ - 4}{9} - \frac{7}{3} ) - \frac{11 }{6}$

$\sf \: LHS = ( \frac{ - 4 - 21 }{9} ) - \frac{11 }{6}$

$\sf \: LHS = \frac{ - 25}{9} - \frac{11 }{6}$

$\sf \: LHS = \frac{ - 50 - 33}{18}$

$\sf \: LHS = \frac{ - 83}{18}$

$\sf \: RHS = a - (b - c)$

$\sf \: RHS = \frac{ - 4}{9} - ( \frac{7}{3} - \frac{11}{6} )$

$\sf \: RHS = \frac{ - 4}{9} - ( \frac{14 - 11}{6} )$

$\sf \: RHS = \frac{ - 4}{9} - \frac{3}{6}$

$\sf \: RHS = \frac{ - 8 - 9}{18}$

$\sf \: RHS = \frac{ - 17}{18}$

LHS≠ RHS

• Hence (a - b) - c ≠a - (b - c)

Answer 2

Answer:

hope this helps you

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