Can anyone give step by step explanation for this as soon as possible
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1
Component of acceleration towards displacement =gsin37
0
=
5
3g
=6 m/s
2
Force in the direction of displacement , F=ma
=0.25×6
=1.5N
Work done against the friction ,W=F s=1.5×1
therefore answer is 1.5J
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Answered by
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Answer:
Work Done = 1.5 J
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