Math, asked by patelaayushi2624, 2 months ago

can anyone help me...​

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Answered by ajr111
2

Answer:

(c) 1/16 is the correct answer

Step-by-step explanation:

Probability P(x) is always equal to 1

P(x) = 1

=> P(x) = c (⁴C₀ + ⁴C₁ + ⁴C₂ + ⁴C₃ + ⁴C₄)

=> 1 = c (1 + 4 + 6 + 4 + 1)

\boxed {\text{We know that $ (^4 _x)$ is written as $^4C_x$ and $^4C_0 = ^4C_4 = 1 ; ^4C_1 = ^4C_3 = 4; $ and $^4C_2 = 6$}}=> 1 = c(16)

=> c = 1/16

Hope it helps

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Answered by keerthyreddy7788
0

Answer:

c. is correct one

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