Question

can anyone help me ​

Answer 1

1. x2-4x-5

x2-5x+x-5

common

x(x-5)+1(x-5)

(x+1) (x-5)

x=-1 & x=5

2.2m2-5m

common

m(2m-5)

we know that we able add 0 so

m+0 is same as m

(m+0) (2m-5)

m=0 & m=5/2

3.a2-25

a2=25

root both side

so

a2 became a but 25 is 5 & -5

therefore

a=5&-5

I hope it help u

thank