can anyone help me
A boy throws a ball upward and after 8 seconds he catch it again then find
a)By which velocity ball was thrown upward
B )At what height the velocity of the ball be zero (9.8 metre per square is =g ]
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a) v=u-gt
0=u-(9.8*4) [time taken to reach the maximum height = 8/2=4 sec]
u=38.2 m/sec
b) maximum height reached = u^2/2g
(38.2*38.2)/(2*9.8)=78.4m
0=u-(9.8*4) [time taken to reach the maximum height = 8/2=4 sec]
u=38.2 m/sec
b) maximum height reached = u^2/2g
(38.2*38.2)/(2*9.8)=78.4m
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