Math, asked by kartik666611, 10 months ago

can anyone help me







EXERCISE 21.1
1. Find the area of a triangle whose
(i) base = 6.6 m and height = 3.5 m
(ii) base = 5.4 cm and height = 8 dm
2. Find the height of the triangle whose
(i) area = 32.8 m², base = 4.1 m
(ii) area = 28 dm, base = 1.4 m
3. Find the base of a triangle whose
(i) area = 8.4 m², height = 2.4 m
(ii) area = 28.56 cm², height = 3.4 cm
4. The base of a right-angled triangle is 8 cm and its hypotenuse is 17 cm. Find the area of the triangle​

Answers

Answered by khushi12321
0

Answer:

1.1/2×6.6×3.5=11.55

Answered by vickyok
1

Answer:

Step-by-step explanation:

area= 1/2 bh

1.i. area=1/2*6.6* 3.5=11.55 cms

ii.area= 1/2*5.4*8=21.6 cm

2.i height =2* area/base

=2 * 32.8/ 4.1= 16 cm

ii. height=2* area/base

= 2* 28* 1.4= 78.4 cms

3.base= 2* area/height

i.2* 8.4/2.4= 7 cms

ii.2* 28.56/3.4=16.8 cms

4. base= 8 cms

 hypotenuse=17 cms

a= 1/2 bh

= 1/2 * 8*17

= 17cm

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