Can anyone help me how to do this que.
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Zeroes are root2 and - root2
=> ( x + root2) and ( x - root2) are factor of given polynomial.
We know that product of two factors of given number is also the factor of given number.
So,
=> ( x^2 - 2) is factor of given polynomial
Now,
On dividing the given polynomial by ( x^2 - 2)
Quotient = ( x^2 + 3x - 18)
Since the Divisor is factor of given polynomial,
The quotient will also be the factor of given polynomial.
Now,
On factorising the quotient,
x^2 + 3x - 18
= x^2 + 6x - 3x - 18
= x ( x +6) - 3(x +6)
= ( x + 6) (x - 3)
Other zeroes are 3 and - 6
=> ( x + root2) and ( x - root2) are factor of given polynomial.
We know that product of two factors of given number is also the factor of given number.
So,
=> ( x^2 - 2) is factor of given polynomial
Now,
On dividing the given polynomial by ( x^2 - 2)
Quotient = ( x^2 + 3x - 18)
Since the Divisor is factor of given polynomial,
The quotient will also be the factor of given polynomial.
Now,
On factorising the quotient,
x^2 + 3x - 18
= x^2 + 6x - 3x - 18
= x ( x +6) - 3(x +6)
= ( x + 6) (x - 3)
Other zeroes are 3 and - 6
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