Can anyone help me.. How to do this.. With steps and graph
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Answer:
given,
2x+y=6....eqn1
2x-y+2=0...eqn2
fromeqn1
2x+y=6
divide throughout by6
x/3+y/6=1
this is interesepht form
then a=3andb=6
from eqn 2
2x-y+2=0
2x-y=-2
divide throughout by-2
x/-1+y/2=1
this is intersect form
here c=-1and d=2
Now we draw graph
HOPE IT WILL HELP YOU IN YOUR STUDY'S ✌️
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