Question

Can anyone help me in solving this question

Answer 1

$\huge {\mathcal{\purple{H}\green{e}\pink{y}\blue{!}}}$

We know that x^3+y^3=(x+y)^3-3xy(x+y)

puting x+y=3 and xy =2 we get,

= (3)^3-3×2(3)

=27-3×6

=27-18

=9

Mark as brainliest please

Answer 2

Answer:

We know that x^3+y^3=(x+y)^3-3xy(x+y)

puting x+y=3 and xy =2 we get,

= (3)^3-3×2(3)

=27-3×6

=27-18

=9