Question

can anyone help me in this question?​

Answer 1

$\huge\underline\mathfrak\pink{Answer}$

1st integer = 11

2nd integer = 12

3rd integer = 13

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$\huge\underline\mathfrak\pink{Explanation}$

Let 1st integer be n.

2nd be n+1.

3rd be n+2.

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According to question,

n + n + 1 + n + 2 = 36

==> 3n + 3 = 36

==> 3n = 36 - 3

==> 3n = 33

==> n = 33/3

==> n = 11

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Therefore, 1st integer be 11.

2nd integer be 11+1 = 12.

3rd integer be 11+2 = 13.

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★Verification :

11+12+13 = 36

36 = 36

☑️ Hence verified!