Can anyone help me in this sum??
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Dear student
since the radius of the cylinder is same as the radius of the one circular plate.
the radius of the base of the cylinder be r = 7 cm
the height of the cylinder is same as the thickness of 50 circular plates.
thickness of 1 plate = 1/2 cm.
therefore the height of the cylinder h = 50*1/2 =25 cm
total surface area of the cylinder = curved surface area of the cylinder + 2*area of the base
volume of the cylinder =
Space left in a cubical box=Volume of box−volume of solid=253−3850=15625−3850=11775cm3
Regards
since the radius of the cylinder is same as the radius of the one circular plate.
the radius of the base of the cylinder be r = 7 cm
the height of the cylinder is same as the thickness of 50 circular plates.
thickness of 1 plate = 1/2 cm.
therefore the height of the cylinder h = 50*1/2 =25 cm
total surface area of the cylinder = curved surface area of the cylinder + 2*area of the base
volume of the cylinder =
Space left in a cubical box=Volume of box−volume of solid=253−3850=15625−3850=11775cm3
Regards
smartAbhishek11:
уα ι тяу ιт αgαιи
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