Question

can anyone help me out ​

Answer 1

Answer:

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

Step-by-step explanation:

$Part \: (B):$

$5x²-22x+8$

$=> 5x²-20x-2x+8$

$=> 5x(x-4)-2(x-4)$

$=> (5x-2)(x-4)$

$Part \: (C):$

$[ Solution \: is \: there \: in \: image]$

$Quotient: \: \: x²+7x+11$

$Remainder: \: 26$

$Part \: (D):$

$Given: XY= ZY \\ and \: \: \: \: \: \: WY \: bisects \: angle \: Y$

$To \: Prove : I) ∆XYW \:=∆ZYW$

$ii) XW=ZW$

$iii)angle \: WXY=angle \: WZY$

$proof:$

$(I)I n \: ∆XYW \: \: and, \: ∆ZYW$

$XY = ZY [ Given]$

$/WZ = /WZ \: \: [ common]$

$XY = ZY \: \: [ WY \: bisects /_Y]$

$By \: SAS ,$

$∆XYW ~=∆ZYW$

$ii) XW = ZW \: \: [ CPCT]$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

$\star \: i \: hope \: you \: will \: understand \: me\star$