Question

Can anyone help me out with this problem? I am not understanding.!!! ​

Answer 1

Step-by-step explanation:

$cos0 . \sin {} (90). \cos ^2 (30). \sec {}^{2} 45 \div \tan60 + \cot60$

$1 \times 1 \times 3 \div 4 \times 2 \div \sqrt{3} + 1 \div \sqrt{3}$

Answer 2

Answer:

3√3/8

Step-by-step explanation:

converting radian values into degrees

cos0°(sin90°)(cos30^2)(sec45^2)/

tan60°+cot60°

so

=(1)(1)(√3/2)^2(√2)^2 /

√3+1/√3

=(3/4)(2) /

(3+1)/√3

=(3/2) /

(4)/√3

=(3/2)(√3/4)

=3√3/8